8x^2-(2x)-3=0

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Solution for 8x^2-(2x)-3=0 equation:


Simplifying
8x2 + -1(2x) + -3 = 0

Remove parenthesis around (2x)
8x2 + -1 * 2x + -3 = 0

Multiply -1 * 2
8x2 + -2x + -3 = 0

Reorder the terms:
-3 + -2x + 8x2 = 0

Solving
-3 + -2x + 8x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -2x)(3 + -4x) = 0

Subproblem 1

Set the factor '(-1 + -2x)' equal to zero and attempt to solve: Simplifying -1 + -2x = 0 Solving -1 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -2x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -2x = 0 + 1 -2x = 0 + 1 Combine like terms: 0 + 1 = 1 -2x = 1 Divide each side by '-2'. x = -0.5 Simplifying x = -0.5

Subproblem 2

Set the factor '(3 + -4x)' equal to zero and attempt to solve: Simplifying 3 + -4x = 0 Solving 3 + -4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4x = 0 + -3 -4x = 0 + -3 Combine like terms: 0 + -3 = -3 -4x = -3 Divide each side by '-4'. x = 0.75 Simplifying x = 0.75

Solution

x = {-0.5, 0.75}

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